432=X^2+2x-8

Solution for 432=X^2+2x-8 equation:

432=X^2+2X-8

We move all terms to the left:

432-(X^2+2X-8)=0

We get rid of parentheses

-X^2-2X+8+432=0

We add all the numbers together, and all the variables

-1X^2-2X+440=0

a = -1; b = -2; c = +440;
Δ = b2-4ac
Δ = -22-4·(-1)·440
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-42}{2*-1}=\frac{-40}{-2}
=+20
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+42}{2*-1}=\frac{44}{-2}
=-22
$